2cos^2(2x)+3cos^2(x)=2

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Solution for 2cos^2(2x)+3cos^2(x)=2 equation:


Simplifying
2cos2(2x) + 3cos2(x) = 2

Remove parenthesis around (2x)
2cos2 * 2x + 3cos2(x) = 2

Reorder the terms for easier multiplication:
2 * 2cos2 * x + 3cos2(x) = 2

Multiply 2 * 2
4cos2 * x + 3cos2(x) = 2

Multiply cos2 * x
4cos2x + 3cos2(x) = 2

Multiply cos2 * x
4cos2x + 3cos2x = 2

Combine like terms: 4cos2x + 3cos2x = 7cos2x
7cos2x = 2

Solving
7cos2x = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '7os2x'.
c = 0.2857142857o-1s-2x-1

Simplifying
c = 0.2857142857o-1s-2x-1

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